Question

An electric charge $2\times {10}^{-8}C$ is placed at the point $\left(1,2,4\right)\text{m}$. The electric potential at the point $\left(4,2,0\right)\text{m}$ will be

• A. $12\text{V}$
• B. $24\text{V}$
• C. $36\text{V}$
• D. $48\text{V}$

Answer 1

The correct option is C $36\text{V}$

The distance between the charge and the point at which electric potential has to be calculated is,
$r=\sqrt{{(4-1)}^2+{(2-2)}^2+{(0-4)}^2}$
$=5\text{m}$
Further the electric potential at the given point due to the point charge is,
$V_P=\frac{kq}{r}$
$V_P=\frac{9\times {10}^9\times 2\times {10}^{-8}}{5}$
$\therefore V_P=36V$