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Faraday's First Law

An electric c...

Question

An electric charge of $5$ Faraday's is passed through three electrolytes $A g N O_{3}$ , $C u S O_{4}$ and $F e C l_{3}$ solution. The grams of each metal liberated at cathode will be:

A g = 10.8 g, C u = 12.7 g, F e = 1.11 g

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A g = 540 g, C u = 367.5 g, F e = 325 g

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A g = 108 g, C u = 63.5 g, F e = 56 g

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A g = 540 g, C u = 158.8 g, F e = 93.3 g

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Solution

The correct option is D $A g = 540 g, C u = 158.8 g, F e = 93.3 g$
$A g^{+} + e^{-} ⟶ A g (1 F ⟶ 1$ $m o l$ of $A g)$
$C u^{2 +} + 2 e ⟶ C u (2$ $m o l ⟶ 1$ $m o l$ of $C u)$
$F e^{3 +} + 3 e^{-} ⟶ F e (3 F ⟶ 1$ $m o l$ of $F e)$
as $5$ $m o l$ Faraday of electricity is passed.
$5$ $m o l$ of $A g$ , $\frac{5}{2}$ $m o l$ of $C u$ and $\frac{5}{3}$ $m o l$ of $F e$ is deposited.
$∴ 5 \times 108$ $g = 540$ $g$ of $A g$
$\frac{5}{2} \times 63.5$ $g = 158.8$ $g$ of $C u$
$\frac{5}{3} \times 56$ $g = 93.3$ $g$ of $F e$
Hence option (D) is correct.

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Similar questions

$E_{F e^{2 +} / F e}^{\circ} = - 0.44 V, E_{C u^{2 +} / C u}^{\circ} = 0.34 V, E_{A g^{2 +} / g}^{\circ} = 0.80 V$ . Will Fe displace Cu from $C u S O_{4}$ solution? Will Ag displace Cu from $C u S O_{4}$ solution?

1. Yes, Yes

2. No, No

3. Yes, No

4. No, Yes

Q. One mole of electron passes through each of the solution of

A g N O_{3}, C u S O_{4}

and

A l C l_{3}

then

A g, C u

and

A l

are deposited at cathode. The molar ratio of

A g, C u

and

A l

deposited are:

Q. In which metal container, the aqueous solution of

C u {S O}_{4}

can be stored?

E_{{C u}^{2 +} / C u}^{o} = 0.34 V

E_{{F e / F e}^{2 +}}^{o} = 0.44 V, E_{{A l / A l}^{3 +}}^{o} = 1.66 V

E_{N i / {N i}^{2 +}}^{o} = 0.25 V, E_{{A g}^{+} / A g}^{o} = 0.80 V

Q. Given that

E_{F e^{2 +} / F e}^{o} = - 0.44, E_{C u^{2 +} / C u}^{o} = 0.34 V, E_{A g + / A g}^{o} = 0.80 V

Which of the following statements are true :

Q. Answer, whether under standard conditions, the following reactions are possible or not:
(i) Will copper reduce

A g^{+}

A g

? Given:

E_{A g^{+} / A g}^{\circ} = 0.799 v o l t; E_{C u^{2 +} / C u}^{\circ} = 0.337 v o l t

.
(ii) Will

F e^{3 +}

be reduced to

F e^{2 +}

S n^{2 +}

ion? Given:

F e^{3 +} / F e^{2 +} = 0.771 v o l t

;

S n^{2 +} / S n^{4 +} = - 0.250 v o l t

(iii) Would you use a silver spoon to stir a solution of

C u (N O_{3})_{2}

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An electric charge of 5 Faraday's is passed through three electrolytes AgNO3, CuSO4 and FeCl3 solution. The grams of each metal liberated at cathode will be:

An electric charge of $5$ Faraday's is passed through three electrolytes $A g N O_{3}$ , $C u S O_{4}$ and $F e C l_{3}$ solution. The grams of each metal liberated at cathode will be: