An electric charge +q moves with velocity v= 3i^ +4j^+k^ is an electromagnetic field given by E= 3i^+j^+2k^ , B=i^+j^+3k^ .The y-component of the force experienced by +q is ?
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Solution
Dear Student,
F = q(E + v x B)
On evaluating v x B we get = (11i - 8j - k)
Hence F = q[( 3i + j + 2k) + ( 11i - 8j -k )]
= q(14i - 7j + k )
The y-component of the force is -7q.