An electric circuit consisting of a $0.5 m$ long nichorome wire $X Y$ , an ammeter, a voltmeter, four cells of $1.5 v$ each and a plug key was set up.
(i) Draw a diagram of this electric circuit to study the relation between the potential difference maintained between the points $^{'} X^{'}$ and $^{'} Y^{'}$ and the electric current flowing through $X Y$ .
(ii) Following graph was plotted between $V$ and $I$ values:
What would be the values of $\frac{V}{I}$ ratios when the potential difference is $0.8 V, 1.2 V$ and $1.6 V$ , respectively? What conclusion do you draw from these values?

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Solution

(i) diagram is attached above

(ii)at potential diff 0.8V, V/I = 0.8/0.3 = 8/3
at potential diff 1.2V, V/I = 1.2/0.45 = 8/3
at potential diff 1.6V, V/I = 1.6/0.6 = 8/3
This shows that the ratio V/I is constant and ohm's law is obeyed

The conclusion is that the resistance is 8/3 Ω

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An electric circuit consisting of a 0.5 m long nichrome wire XY, an ameter, a voltmeter four cells of 1.5 V each and a plug key was set up.
(i) Draw a diagram of this electric circuit to study the relation between the potential difference maintained between the points 'X' and 'Y' and the electric current flowing through XY.
(ii) Folloiwng graph was plotted between V and I values:
What would be the values of $\frac{V}{I}$ ratios when hte potential difference is 0.8 V, 1.2 V and 1.6 vrespectively ?
What conclusion do you draw from these values?

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(i)

(ii)

(c) An electric circuit consisting of a 0.5 m long nichrome wire XY, an ammeter, a voltmeter, four cells of 1.5 V each and a plug key was set up.
(i) Draw a diagram of this electric circuit to study the relation between the potential difference maintained between the points 'X' and 'Y' and the electric current flowing through XY.
(ii) Following graph was plotted between V and I values:

What would be the values of

\frac{V}{I}

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Current, I (in amperes)	:	0.1	0.2	0.4	0.6	0.8	1.0

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(i) diagram is attached above(ii)at potential diff 0.8V, V/I = 0.8/0.3 = 8/3at potential diff 1.2V, V/I = 1.2/0.45 = 8/3at potential diff 1.6V, V/I = 1.6/0.6 = 8/3This shows that the ratio V/I is constant and ohm's law is obeyedThe conclusion is that the resistance is 8/3 Ω

(i) diagram is attached above

(ii)at potential diff 0.8V, V/I = 0.8/0.3 = 8/3
at potential diff 1.2V, V/I = 1.2/0.45 = 8/3
at potential diff 1.6V, V/I = 1.6/0.6 = 8/3
This shows that the ratio V/I is constant and ohm's law is obeyed

The conclusion is that the resistance is 8/3 Ω