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Question

An electric current i is flowing in a circular coil of radius a. At what distance from the center of the axis of the coil will the magnetic field be 18th of its value at the centre?

A
3a
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B
3a
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C
a3
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D
a3
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Solution

The correct option is B 3a
Magnetic field due to the circular current (I) carrying coil of radius a, at a distance r from the center of the coil is given by:
B1=μ04π2πa2I(z2+a2)3/2.
Now the field at a point P.B1will be 18th times the field at the center:
So, B=8B1
or, μ0I2a=8×μ04π2πa2I(z2+a2)3/2
for, z=3a
77822_89304_ans.png

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