The reaction taking place at anode is :
2Cl−→Cl2+2e−
Q=I*t = 100*5*60*60 coulumb
The amount of chlorine liberated by passing 100*5*60*60 coulumb of electric charge =12∗96500*100*5*60*60 = 9.3264 mole
Volume of Cl2 liberated at NTP = 9.3264*22.4 = 208.91L.