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Question

An electric dipole consisting of two opposite charges of 2×106 C each, separated by a distance of 3 cm is placed in an electric field of 2×105 N/C. The maximum torque on the dipole will be

A
12×101 Nm
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B
12×103 Nm
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C
24×101 Nm
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D
24×103 Nm
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Solution

The correct option is B 12×103 Nm
Let 2d be the separation between the charges of a dipole.
So, we can write 2d=3 cm

We know that torque acting on the dipole due to electric field is given by
τ=P×E
(Here P is dipole moment and E is electric field)
τ=PE sinθ

For τ to be maximum, the angle between dipole moment and electric field must be 900
τmax=PE
τmax=(q×2d)(2×105 N/C)
τmax=(2×106×3×102×2×105) Nm
τmax=12×103 Nm

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