An electric dipole is along a uniform electric field If it is deflected by 60∘, work done by agent is2×10−19J . Then the work done by an agent if it is isdeflected by 30∘ further is
A
2.5×10−19J
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B
2.0×10−19J
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C
4.0×10−19J
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D
2.0×10−16J
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Solution
The correct option is B2.0×10−19J Working on electric dipole when deflected by an angle of 600 is given by,
W1=U=−PEcos600=−2×10−19J.
Now, work done in deflecting he dipole by another 300 is given by,
W1=−PEcos900=0
Therefore work done by the agency which deflected dipole by 300 mpore is,