An electric dipole is an arrangement of two equal charges of equal magnitude but opposite nature, separated by some fixed distance.

Now consider a dipole enclosed inside a closed surface S. The flux through the surface S is zero.

True

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false

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Solution

The correct option is A
True

Gauss’s law states, $ϕ_{c l o s e d s u r f a c e} \frac{q_{i n}}{ϵ_{0}} = \frac{q - q}{ϵ_{0}} = 0$

Hence no electrical flux through the surface which also implies that the number of field lines leaving the surface is equal to number of field lines entering it.

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An electric dipole is an arrangement of two equal charges of equal magnitude but opposite nature, separated by some fixed distance. Now consider a dipole enclosed inside a closed surface S. The flux through the surface S is zero.

The correct option is A True Gauss’s law states, ϕclosed surfaceqinϵ0=q−qϵ0=0 Hence no electrical flux through the surface which also implies that the number of field lines leaving the surface is equal to number of field lines entering it.

An electric dipole is an arrangement of two equal charges of equal magnitude but opposite nature, separated by some fixed distance.

Now consider a dipole enclosed inside a closed surface S. The flux through the surface S is zero.

The correct option is A
True

Gauss’s law states, $ϕ_{c l o s e d s u r f a c e} \frac{q_{i n}}{ϵ_{0}} = \frac{q - q}{ϵ_{0}} = 0$

Hence no electrical flux through the surface which also implies that the number of field lines leaving the surface is equal to number of field lines entering it.