An electric dipole is placed at an angle 30∘ with an electric field intensity 2×105NC−1. It experiences a torque equal to 4Nm. The charge on the dipole(in mC), if the dipole length is 2cm, is
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Solution
We know that torque is given by ∣→τ∣=∣→p×→E∣⇒τ=pEsinθ⇒4=q×2×10−2×2×105×12⇒q=2×10−2=2mC