An electric dipole is placed at an angle 30- with an electric field intensity 2 - 105 NC -1- It experiences a torque equal to 4 N m- The charge on the dipolein mC - if the dipole length is 2 cm- is

We know that torque is given by |τ⃗|=|p⃗×E⃗| ⇒τ=pEsinθ ⇒4=q×2×10^ 2× 2×10^5×1/2 ⇒ q=2×10^ 2=2 mC ...

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Standard XII

Physics

Torque on a Dipole

An electric d...

Question

An electric dipole is placed at an angle $30^{\circ}$ with an electric field intensity $2 \times 10^{5} N C^{- 1}$ . It experiences a torque equal to $4 N m$ . The charge on the dipole(in $m C$ ), if the dipole length is $2 c m$ , is

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Solution

We know that torque is given by
$∣ \to τ ∣=∣ \to p \times \to E ∣ \Rightarrow τ = p E sin θ \Rightarrow 4 = q \times 2 \times 10^{- 2} \times 2 \times 10^{5} \times \frac{1}{2} \Rightarrow q = 2 \times 10^{- 2} = 2 m C$

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An electric dipole is placed at an angle 30∘ with an electric field intensity 2×105NC−1. It experiences a torque equal to 4Nm. The charge on the dipole(in mC), if the dipole length is 2 cm, is

We know that torque is given by ∣→τ∣=∣→p×→E∣⇒τ=pEsinθ⇒4=q×2×10−2×2×105×12⇒q=2×10−2=2 mC

An electric dipole is placed at an angle $30^{\circ}$ with an electric field intensity $2 \times 10^{5} N C^{- 1}$ . It experiences a torque equal to $4 N m$ . The charge on the dipole(in $m C$ ), if the dipole length is $2 c m$ , is

We know that torque is given by
$∣ \to τ ∣=∣ \to p \times \to E ∣ \Rightarrow τ = p E sin θ \Rightarrow 4 = q \times 2 \times 10^{- 2} \times 2 \times 10^{5} \times \frac{1}{2} \Rightarrow q = 2 \times 10^{- 2} = 2 m C$