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Question

An electric dipole is placed at an angle of 30 with an electric field intensity 2×105 N/C. It experiences a torque equal to 4 N-m. The charge on the dipole, if the dipole length is 2 cm is

A
4 μC
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B
2 mC
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C
2 μC
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D
4 mC
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Solution

The correct option is B 2 mC
Given:
E=2×105 N/C; τ=4 N-m
l=2 cm=2×102 m

Torque experienced by a dipole placed in uniform electric field is
τ=p×E

The magnitude of torque will be

τ=pEsinθ

τ=(ql)Esinθ

q=τlEsinθ

q=42×102×2×105×12

q=2×103 C=2 mC

Hence, option (b) is correct.


Why this question?Tip: The torque acting on dipole is always rto plane of Eand dipole moment vector (P).

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