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Magnetic Flux and Faraday's Law

An electric d...

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An electric dipole of dipole moment p is placed in the position of stable equilibrium in uniform electric field of intensity E. This is rotated through an angle theta from the initial position the potential energy of the electric dipole in the final position is

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Q. An electric dipole of moment p is placed in the position of stable equilibrium in uniform electric field of intensity E. If it is rotated through an angle

θ

from the initial position, the potential energy of electric dipole in the final position is

Q. An electric dipole (dipole moment

= p

) is placed in a uniform electric field in stable equilibrium position at rest. Now it is rotated by a small angle and released. The time after which it comes to the equilibrium position again (for first time) is

t

. Then the moment of inertia of the dipole about the axis of rotation is :

Q. An electrical dipole of dipole moment

^{'} p^{'}

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^{'} E^{'}

. The dipole acquires a position such that the axis of the dipole makes an angle

θ

with electric field. Assuming that the potential energy of the dipole to be zero when

θ = 90^{\circ}

, the torque on dipole and the potential energy of the dipole will be respectively

Q. Calculate the amount of work done in turning an electric dipole of dipole moment

3 \times 10^{- 8} C

-m from its position of unstable equilibrium to the position of stable equilibrium in a uniform electric field of intensity

10^{3} N C^{- 1}

Q. An electric dipole of moment 'p' is placed in an electric field of intensity 'E'. The dipole acquires a position such that the axis of the dipole makes an angle

θ

with the direction of the field. Assuming that the potential energy of the dipole to be zero when=

90^{0}

, the torque and the potential energy of the dipole will respectively be

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