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Question

An electric dipole of length 10 cm having charges 6×103 C is placed at 60 with respect to a uniform electric field. If it experiences a torque of 33 N-m, then the magnitude of electric field is

A
1×104 N/C
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B
2×104 N/C
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C
3×104 N/C
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D
4×104 N/C
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Solution

The correct option is A 1×104 N/C
Given:
2l=10 cm=0.1 m; q=±6×103 C
θ=60; τ=33 N-m

Torque acting on dipole placed in electric field is given by

τ=pEsinθ=(q×2l)Esinθ

E=τ(q 2l)sinθ=336×103×0.1×sin60

E=336×103×0.1×32

E=104 N/C

Hence, option (a) is correct.

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