An electric dipole of length 4cm when placed with its axis making an angle of 60 - with a uniform electric field- experience a torque of 4-3 N - m- Calculate the potential energy of the dipole of it has charge - 8nC-

Dipole moment(P) = q.2L P=8× 10 ^ 9 × 2× 4× 10 ^ 2 =64× 10 ^ 11 Cm Torque on the dipole in uniform electric field τ =PEsinθ E=τ #160; ...

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Standard XII

Physics

Potential Energy of a Dipole in Uniform Electric Field

An electric d...

Question

An electric dipole of length 4cm when placed with its axis making an angle of $60^{\circ}$ with a uniform electric field, experience a torque of $4 \sqrt{3} N - m$ . Calculate the potential energy of the dipole of it has charge $\pm 8 n C$ .

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Solution

Dipole moment(P) = q.2L
$P = 8 \times 10^{- 9} \times 2 \times 4 \times 10^{- 2} = 64 \times 10^{- 11} C m$
Torque on the dipole in uniform electric field

$τ = P E s i n θ E = \frac{τ}{P s i n θ}$
Potential energy of the dipole is

$U = - P E c o s θ$
on substituting the value , we get the value of E and U

$U = - P \frac{τ}{P s i n θ} c o s θ = - \frac{τ}{t a n θ}$

$U = - \frac{4 \sqrt{3}}{\sqrt{3}} = - 4 N m$

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An electric dipole of length 4cm when placed with its axis making an angle of 60∘ with a uniform electric field, experience a torque of 4√3N−m. Calculate the potential energy of the dipole of it has charge ±8nC.

Dipole moment(P) = q.2LP=8×10−9×2×4×10−2=64×10−11CmTorque on the dipole in uniform electric fieldτ=PEsinθE=τPsinθPotential energy of the dipole is U=−PEcosθon substituting the value , we get the value of E and UU=−PτPsinθcosθ=−τtanθU=−4√3√3=−4Nm

An electric dipole of length 4cm when placed with its axis making an angle of $60^{\circ}$ with a uniform electric field, experience a torque of $4 \sqrt{3} N - m$ . Calculate the potential energy of the dipole of it has charge $\pm 8 n C$ .