An electric discharge is passed through a mixturecontaining 50 c.c. of O2and 50 c.c. of H2. The volume of the gases formed (i) at room temperature and (ii) at 1100C will be
A
(i) 25 c.c. (ii) 50 c.c.
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B
(i) 50 c.c. (ii) 75 c.c.
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C
(i) 25 c.c. (ii) 75 c.c.
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D
(i) 75 c.c. (ii) 75 c.c.
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Solution
The correct option is C(i) 25 c.c. (ii) 75 c.c. At room temperature2H2(g)+O2(g)→2H2Olt=050ml50ml0t=t50−2x50−x2x=025gases(50)liquid In this case H2is limiting reagent x=25ml
At 110∘C2H2(g)+O2(g)→2H2O(g)Vgas=75mlt=t025ml2×50ml