An electric fan has blades of length 30 cm as measured from the axis of rotation. If the fan is rotating at 1200 r.p.m. The acceleration of a point on the tip of the blade is about

$1600 m / s e c^{2}$

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$4740 m / s e c^{2}$

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$2370 m / s e c^{2}$

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$5055 m / s e c^{2}$

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Solution

The correct option is B
$4740 m / s e c^{2}$

$ω^{2} r = 4 π^{2} n^{2} r = 4 π^{2} {(\frac{1200}{60})}^{3} \times 30 = 4740 m / s^{2}$

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An electric fan has blades of length 30 cm as measured from the axis of rotation. If the fan is rotating at 1200 r.p.m. The acceleration of a point on the tip of the blade is about

The correct option is B 4740 m/sec2 ω2r=4π2n2r=4π2(120060)3×30=4740 m/s2

The correct option is B
$4740 m / s e c^{2}$

$ω^{2} r = 4 π^{2} n^{2} r = 4 π^{2} {(\frac{1200}{60})}^{3} \times 30 = 4740 m / s^{2}$