An electric field exists in space as E- - 2i- - 3j- - 0k- Find the potential difference VA-VB between points A2-2-0 and B1-1-0

A circuit
has a section AB as shown in figure with E= $10 V, C_{1} =$ 1.0 $μ F$ $C_{2} = 2 .0$ $μ F$ and the potential difference $V_{A} - V_{B} = 5 V$ The
voltage across $C_{1}$ is :

Q. An electric field of 20 NC⁻¹ exists along the x-axis in space. Calculate the potential difference V_B − V_A where the points A and B are
(a) A = (0, 0); B = (4 m, 2m)
(b) A = (4 m, 2 m); B = (6 m, 5 m)
(c) A = (0, 0); B = (6 m, 5 m)
Do you find any relation between the answers of parts (a), (b) and (c)?

Q. A battery of EMF 5 V and internal resistance 0.2

Ω

is being charged with a current of 10 A as shown. What is the potential difference between the terminals of the battery i.e.

V_{A} - V_{B}

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An electric field exists in space as →E = 2→i + 3→j + 0→k. Find the potential difference (VA−VB) between points A(2,2,0) and B(1,1,0)

The correct option is B + 5 V→E = 2→i + 3→j + 0→kA(2,2,0) or →A = 2→i + 2→j + 0→k andB(1,1,0) or →A = →i + →j + 0→kVA=→E.→A=( 2→i + 3→j + 0→k).( →i + →j + 0→k)=4+6+0=10 vollt.VB=( 2→i + 3→j + 0→k).( →i + →j + 0→k)=5 voltVA−VB=10−5=+5V

An electric field exists in space as $\to E = 2 \to i + 3 \to j + 0 \to k$ . Find the potential difference $(V_{A} - V_{B})$ between points $A (2, 2, 0)$ and $B (1, 1, 0)$