An electric field of 1000 V-m- is applied to an electric dipole moment of 10-29 C- m- What is the potential energy of the electric dipole-

Potential energy of a dipole is given nbsp; by, U= P·E nbsp; nbsp; = PEcos θ Where, θ= angle between dipole moment vector and the field U= (10^ 29)( ...

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Standard XII

Physics

Potential at a General Point Due to a Dipole

An electric f...

Question

An electric field of $1000 V/m$ , is applied to an electric dipole moment of $10^{- 29} C \cdot m .$ What is the potential energy of the electric dipole?

- 20 \times 10^{- 18} J

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- 7 \times 10^{- 27} J

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- 10 \times 10^{- 29} J

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- 9 \times 10^{- 20} J

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Solution

The correct option is B $- 7 \times 10^{- 27} J$
Potential energy of a dipole is given by,

$U = - \to P \cdot \to E$
$= - P E cos θ$

$Where, θ = angle between dipole moment vector and the field$

$U = - (10^{- 29}) (10^{3}) cos 45^{\circ} \approx - 7 \times 10^{- 27} J$

Hence, $(B)$ is the correct answer.

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An electric field of 1000 V/m, is applied to an electric dipole moment of 10−29 C⋅m. What is the potential energy of the electric dipole?

The correct option is B −7×10−27JPotential energy of a dipole is given by, U=−→P⋅→E =−PEcos θ Where, θ= angle between dipole moment vector and the field U=−(10−29)(103)cos45∘≈−7×10−27 J Hence, (B) is the correct answer.

An electric field of $1000 V/m$ , is applied to an electric dipole moment of $10^{- 29} C \cdot m .$ What is the potential energy of the electric dipole?