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Question

An electric field of 1000 V/m, is applied to an electric dipole moment of 1029 Cm. What is the potential energy of the electric dipole?

A
10×1029J
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B
9×1020J
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C
20×1018J
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D
7×1027J
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Solution

The correct option is D 7×1027J
Potential energy of a dipole is given by,

U=PE
=PEcos θ

Where, θ= angle between dipole moment vector and the field

U=(1029)(103)cos457×1027 J

Hence, (B) is the correct answer.

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