Question

An electric field $\overrightarrow{E}-\overrightarrow{i}Ax$ exists in the space, where $A=V/m^2$. take the potential at $(10m,20m)$ to be zero. Find the potential at the origin.

Answer 1

We know electric field $E=\frac{-dV}{dx}$

$-dV=Axdx$

Integrating both sides we get

$V=-\frac{A{x}^2}{2}+C$------------(A)

Now at x=10,20 V=0

$0=-\frac{400-100}{2}A+C$

$C=150A$

Putting the above value in A also $A=V/m^2$we get,

$V=150V/m^2$