An electric heater connected to a 220V lines has two resistance coils of 22 Ohms each. Calculate the current if these coils are used:

a) Separately
b) In Series
c) In Parallel

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Solution

(i) Separately: Current , $I = \frac{V}{R} = \frac{220}{22} = 10 A$

(ii) Series $R = R_{1} + R_{2} = 44 Ω$

$I = \frac{220}{44} = 5 A$

(iii) In Parallel

$\frac{1}{R} = \frac{1}{R_{1}} + \frac{1}{R_{2}} = \frac{1}{22} + \frac{1}{22} = \frac{1}{11}$

$R = 11 Ω$

$I = \frac{220}{11} = 20 A$

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An electric heater connected to a 220V lines has two resistance coils of 22 Ohms each. Calculate the current if these coils are used: a) Separately b) In Series c) In Parallel

(i) Separately: Current , I=VR=22022=10A (ii) Series R=R1+R2=44Ω I=22044=5A (iii) In Parallel 1R=1R1+1R2=122+122=111 R=11Ω I=22011=20A

An electric heater connected to a 220V lines has two resistance coils of 22 Ohms each. Calculate the current if these coils are used:

a) Separately
b) In Series
c) In Parallel

(i) Separately: Current , $I = \frac{V}{R} = \frac{220}{22} = 10 A$

(ii) Series $R = R_{1} + R_{2} = 44 Ω$

$I = \frac{220}{44} = 5 A$

(iii) In Parallel

$\frac{1}{R} = \frac{1}{R_{1}} + \frac{1}{R_{2}} = \frac{1}{22} + \frac{1}{22} = \frac{1}{11}$

$R = 11 Ω$

$I = \frac{220}{11} = 20 A$