Question

An electric heater converts $1kJ$ of electrical energy to heat energy every second with $100\%$ efficiency. The power produced is :

• A. $1W$
• B. $1kW$
• C. $1MW$
• D. $1kJ$

Answer 1

The correct option is B $1kW$

As we know that efficiency=$\frac{P_{out}}{P_{in}}$.
$\eta$=100%
so,$P_{out}$=$P_{in}\times \eta$
$P_{out}$=$\frac{1000\times 100}{100}$= 1kw