an electric heater of power 1600 W has a resistance of 36 ohm calculate the magnitude of the current on the potential difference at its end.

Open in App

Solution

$1600 = I^{2} 36 I = \frac{400}{6} A 1600 = V * \frac{400}{6} V = 24 v o l t R e g a r d s$

Suggest Corrections

Similar questions

An electric bulb of resistance $500 Ω$ draws current 0.4 A from the source. Calculate: (a) the power of bulb and (b) the potential difference at its end.

Q. An electric bulb of resistance

20 Ω

draws a current of

0.04 A

. Calculate the potential difference at the ends.

Q. If an electric heater consumes electricity at the rate of

500 W

and the potential difference between the two terminals of the electric circuit is

250 V

, calculate the electric current passing through the heater and resistance of it respectively.

Q. Calculate the power loss in an electrical transmission cable, 15 km long, carrying a current of 100A at a potential difference of 200kV. The resistance per km of the cable is 0.2 ohm.

Q. If an electric heater consumes electricity at the rate of

500 W

and the potential difference between the two terminals of the electric circuit is

250 V

, calculate the electric current passing through the heater and resistance of it respectively.

Join BYJU'S Learning Program

an electric heater of power 1600 W has a resistance of 36 ohm calculate the magnitude of the current on the potential difference at its end.

1600=I236I=4006 A1600=V*4006V=24 voltRegards

$1600 = I^{2} 36 I = \frac{400}{6} A 1600 = V * \frac{400}{6} V = 24 v o l t R e g a r d s$