wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

An electric heater of power 600 W raises the temperature of 4.0 kg of a liquid from 10.0oC to 15.0oC in 100 s. Calculate the specific heat capacity of liquid:

A
3×103 Jkg1K1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
12×103 Jkg1K1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1.2×103 Jkg1K1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 3×103 Jkg1K1
Heat supplied by water is, Q=600×100
Also, Q=mcΔT
Heat capacity, c=Q/mΔT=3×103Jkg1K1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon