Question

An electric heater of power 600 W rasies the temperature of 4.0 kg of a liquid from ${10.0}^{\circ }Cto{15.0}^{\circ }C$ in 100 s.Calculate:(i) the heat capacity of 4.0 kg of liquid,and(ii) the specific heat capacity of liquid.

Answer 1

Heat required $Pt=ms\Delta T$

$\Rightarrow 600\times 100=4\times S\times (15-10)$

$\Rightarrow S=3000J/kgK$

Now, heat capacity, $C=mS=4\times 3000=12000J/K$