An electric heater of resistance $8 Ω$ draws $15 A$ from the service mains $2$ hours. Calculate the rate at which heat is developed in the heater.

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Solution

Rate of generating heat is equal to the power used by the heater.
By Joule's Law of heating,
$P = I^{2} R$
$= 15^{2} \times 8$
$= 1800 W$
Hence, rate of generation of heat is $1800 W$ .

Total amount of heat generated, $E = P t$
$E = 1800 \times 2 = 3.6 k W h$

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An electric heater of resistance 8 Ω draws 15A from the service mains 2 hours. Calculate the rate at which heat is developed in the heater.

Rate of generating heat is equal to the power used by the heater.By Joule's Law of heating, P=I2R =152×8 =1800 WHence, rate of generation of heat is 1800W.Total amount of heat generated, E=Pt E=1800×2=3.6 kWh

An electric heater of resistance $8 Ω$ draws $15 A$ from the service mains $2$ hours. Calculate the rate at which heat is developed in the heater.

Rate of generating heat is equal to the power used by the heater.
By Joule's Law of heating,
$P = I^{2} R$
$= 15^{2} \times 8$
$= 1800 W$
Hence, rate of generation of heat is $1800 W$ .

Total amount of heat generated, $E = P t$
$E = 1800 \times 2 = 3.6 k W h$