Question

# An electric heater of resistance $$\displaystyle 100\Omega$$ is connected to a main supply for 20 minutes. If 2A current flows through the filament of the heater, calculate the heat energy produced in the heater.

A
4.8×105J
B
400J
C
626J
D
357J

Solution

## The correct option is A $$\displaystyle 4.8\times { 10 }^{ 5 }J$$Given :   $$R = 100\Omega$$           $$t = 20\times 60 = 1200$$ s             $$I =2$$ A$$\therefore$$ Heat energy produced      $$H = I^2Rt = 2^2\times 100\times 1200 = 4.8\times 10^5$$ JPhysics

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