1
Question
An electric heater supplies heat to a system at a rate of 100 W. If system performs work at a rate of 75 joules per second. At what rate is the internal energy increasing?
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Solution
Heat supplied by electric heater,△Q=100 W=100 J/s.
Work done by the system, △W=75 J/s.
According to First Law of Thermodynamics,
the change in internal energy is given by,
△U=△Q −△W
△U=100−75=25 Js−1.
△U=25 W.
Work done by the system, △W=75 J/s.
According to First Law of Thermodynamics,
the change in internal energy is given by,
△U=△Q −△W
△U=100−75=25 Js−1.
△U=25 W.
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