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Question

An electric immersion heater is switched on for $8$ minutes. The heat supplied by it raises the temperature of $500$ g of water from $10^{o}$ C to $60^{o}$ C. Calculate the power of heater in watts.

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Solution

Considering the system to be isolated from the surrounding.
Energy required to raise the temperature of water by 50 degrees is $0.5 k g \times 4200 \times 50 = 105 K J .$
Power of heater=energy per unit time= $\frac{105000}{8 \times 60} = 218.75 W$

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