An electric iron consumes 66 kJ in two minutes at a voltage of 220 V. What would be the amount of current flowing through it?

4.5 A

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5.5 A

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3.5 A

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2.5 A

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Solution

The correct option is D $2.5 A$
Given that electric iron consumes $66 k J$ of energy in $12 m i n u t e s$ at voltage of $220 V$
$⟹$ $W = 66 k J$ $= 66, 000 J$
$t = 2 \times 60$ $= 120 s e c$
$V = 220 V$

We know that the electrical power is the electrical energy consumed by a device in an interval of time
$∴$ $P = \frac{W}{t}$ $= \frac{66, 000 J}{120 s}$ $= 550 W$

The amount of electric current flowing through the device:
$I = \frac{P}{V}$ $= \frac{550 V}{220 A}$ $= 2.5 A$

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