I think something missing from question ,
if question : An electric iron draws a current of 0.5A.The voltage is 200V. Calculate the amount of charge flowing through it in 1 hour
Ans:
We know that,
I = Q/t
0.5A = Q/1hour [1 hour = 60 min = 3600 sec]
0.5A = Q/3600s
Q = 0.5×3600
Q = 1800 C (charge)