Question

An electric iron is rated $220\mathrm{V},1KW$. Under normal working conditions, find the resistance of the heating element in the iron.

Answer 1

Step 1: Given data:

The voltage of electric iron $=220V$

Power of electric iron $=1KW$

Step 2: Calculation of resistance:
The formula for finding the power when voltage and resistance is given is:
$P=\frac{V^2}{R}$,
Where $PisthePower,VistheVoltage,RistheResis\tan ce$

So, for determining the value of resistance we will put the given value in above expression,

Thus the value of the resistance will be

$$\begin{gathered} R=\frac{V^2}{P} \\ =\frac{220\times 220}{1000} \\ =48.4\Omega \end{gathered}$$

Hence, value of the resistance of the electric iron will be $48.4\Omega$