An electric iron is rated $220 V, 1 K W$ . Under normal working conditions, find the amount of current that will flow through the element

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Solution

Step 1: Given data:
The voltage of electric iron $= 220 V$
Power of electric iron $= 1 K W$
Step 2: Calculation of current
As we know,
The formula for finding the power when voltage and current is given is:
$P = V I$ ,
where $P i s t h e P o w e r, V i s t h e V o l t a g e, I i s t h e C u r r e n t$
So, for determining the value of current we will put the given value in above expression,
Thus the value of the current will be
$I = \frac{P}{V} = \frac{1000}{220} = 4.54 A m p .$
Hence, value of the current of the electric iron will be $4.54 A m p .$

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