Question

An electric iron resistor $30\Omega$ take current at $10A$. Calculate the heat developed in $20s$.

Answer 1

$\begin{array}{c}R=30\Omega \\ I=10A\\ t=20s\\ Heat,developed=H=I^{2}Rt\\ H={\left(10\right)}^2\times 30\times 20\\ H=60000Joule=60KJ\end{array}$