An electric iron uses 300 kJ of electrical energy in 2 minutes. What is the rate of power of the electric iron?

1.5 k W

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2.2 k W

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2.5 k W

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2.8 k W

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Solution

The correct option is C $2.5 k W$
Energy used $= 300 k J; T i m e = m i n = 120 s$
As, Power $= \frac{E n e r g y}{T i m e} = \frac{300}{120} = 2.5 k W$

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