Given:
Power, P= 1 KW = 1000 W
Voltage, V = 220V
P = V I
⇒1000=220×I
⇒I=1000220=4.54 A
As we have only 2A, 4A and 5 A fuse.
Rating of the fuse to be used should be slightly more than the current flowing through it, hence the fuse will be of 5 A. [1 Mark]