An electric kettle for use in a 230 V supply is rated at 3000 W. For safe working what should be the current carried by a cable connected to it?
Step 1, Given data
Potential difference , v = 230 v
Power = 3000 W
Step 2, Finding the current
We know,
Power = V×I
Putting all the values
3000=230×I
Or,I=3000230=13.04A
Hence the current flowing is 13.04 A