Question

An electric kettle is rated at 230 V, 1000 W. What is the resistance of its element?

• A. 63.5 Ώ
• B. 52.9 Ώ
• C. 59.2 Ώ
• D. 65.3 Ώ

Answer 1

The correct option is B

52.9 Ώ

Given: Power (P) = 1000 W and Voltage (V) = 230 V

We know that P = $\frac{{\text{V}}^2}{\text{R}}$

$\therefore$ Effective resistance of its element (R) = $\frac{{\text{V}}^2}{\text{P}}$ = $\frac{230\times 230}{1000}$ = 52.9 Ω