CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

An electric kettle is rated at 230 V, 1000 W. What is the resistance of its element? 



Your Answer
A

63.5 Ώ

Correct Answer
B

52.9 Ώ

Your Answer
C

59.2 Ώ

Your Answer
D

65.3 Ώ


Solution

The correct option is B

52.9 Ώ


Given: Power (P) = 1000 W and Voltage (V) = 230 V

We know that P = V2R

Effective resistance of its element (R) = V2P = 230×2301000 = 52.9 Ω

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More


People also searched for
View More



footer-image