Resistance of electric lamp,
R1=100Ω Resistance of toaster,
R2=50Ω Resistance of water filter,
R3=500Ω Potential difference of the source, V = 220 V
These are connected in parallel, as shown in the following figure.
Let R be the equivalent resistance of the circuit. 1R=1R1+1R2+1R3=1100+150+1500 =
5+10+1500 =
16500 According to Ohm’s law, V = IR
I=VR Where,current flowing through the circuit = I
I=22050016=22016500=7.04A 7.04 A of current is drawn by all the three given appliances.
Therefore, current drawn by an electric iron connected to the same source of potential 220 V = 7.04 A
Let R’ be the resistance of the electric iron.
According to Ohm’s law, V = IR’
R′=VI=2207.04=31.25Ω Therefore, the resistance of the electric iron is 31.25Ω and the current flowing through it is 7.04 A.