wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Question 2
An electric lamp of 100Ω, a toaster of resistance 50Ω, and a water filter of resistance 500Ω are connected in parallel to a 220 V source. What is the resistance of an electric iron connected to the same source that takes as much current as all three appliances, and what is the current through it?

Open in App
Solution

Resistance of electric lamp, R1=100Ω
Resistance of toaster, R2=50Ω
Resistance of water filter, R3=500Ω
Potential difference of the source, V = 220 V
These are connected in parallel, as shown in the following figure.

Let R be the equivalent resistance of the circuit.
1R=1R1+1R2+1R3=1100+150+1500 = 5+10+1500 = 16500
According to Ohm’s law, V = IR
I=VR
Where,current flowing through the circuit = I
I=22050016=22016500=7.04A
7.04 A of current is drawn by all the three given appliances.
Therefore, current drawn by an electric iron connected to the same source of potential 220 V = 7.04 A
Let R’ be the resistance of the electric iron.
According to Ohm’s law, V = IR’
R=VI=2207.04=31.25Ω
Therefore, the resistance of the electric iron is 31.25Ω and the current flowing through it is 7.04 A.

flag
Suggest Corrections
thumbs-up
42
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Combination of Resistances
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon