Question

An electric lamp uses energy at the rate of $48\text{W}$ on a $12\text{V}$ supply. The charge passes through it in $2\text{s}$ is -

• A. $4\text{C}$
• B. $8\text{C}$
• C. $48\text{C}$
• D. $18\text{C}$

Answer 1

The correct option is B $8\text{C}$

We know that,

$P=VI$

$\Rightarrow I=\frac{P}{V}=\frac{48}{12}=4\text{A}$

Further,

$I=\frac{q}{t}$

$\Rightarrow q=It=4\times 2=8\text{C}$

Hence, option $\left(B\right)$ is the correct answer.