An electric motor labelled 5KW is able to raise a load at speed of 25 m/s. Calculate the load being lifted.
200N
264N
248N
206N
P = F ´ v Þ 5000 = F ´ 25 Þ F = 200N
The power of a motor is 40 kW.At what speed can the motor raise a load of 20,000 N?