Question

An electric motor of power $1000W$ , operates at $250V$ . Calculate the inductive resistance of the motor and current flowing through it.

Answer 1

Step 1: Calculating the inductive resistance of the motor $R$ :

Given data :

$V=250V$

$P=1000W$

The resistance in the given case is,

$P=\frac{V^2}{R}$

$R=\frac{V^2}{P}$

$=\frac{250\times 250}{1000}$

$=\frac{62500}{1000}$

$=62.5\Omega$

Therefore, the inductive resistance of the motor $R$ is $62.5\Omega$.

Step 2: Determining the current flowing through it:

$I=\frac{V}{R}$

$=\frac{250}{62.5}$

$I=4A$

Therefore, the current flowing is $4A$.