Question

An electric motor of power 300 W is used to drive the stirrer in a water bath. The work done in one minute, if 60 % of the energy of the motor is utilized to drive the stirrer will be

• A. 10,800 J
• B. 1080 J
• C. 1,08,000 J
• D. 108 J

Answer 1

The correct option is A 10,800 J

Input power to stirrer $=0.6\times 300W$ $=180W$

Work done by stirrer $=p\times t$
$=180\times 60$
$=10800J$