An electric pump is $60 %$ efficient and is rated $2 H P$ . Calculate the maximum amount of water it can lift through a height of $5 m$ in $40 s$ . [Take $g = \frac{10 m}{s^{2}}$ and $1 H P = 750 W$ ]

Open in App

Solution

Step 1: Given data,
Efficiency= $60 %$
Power= $2 H P$
Height= $5 m$
Time= $40 s$
Acceleration due to gravity $g = \frac{10 m}{s^{2}}$
$1 H P = 750 W$
Let ‘m’ mass of water can be lifted.
Step 2: To convert horsepower into watts,
$1 H P = 750 W$
$2 H P = 1500 W$
Step 3: To find the power that is efficiently used:
P' = $60 % o f 1500$
$= \frac{60}{100} \times 1500 = 900 w a t t s$
Step 4: To find force and work done,
Formula used : $f o r c e = w e i g h t = m g$
$f o r c e = m \times 10 N$
Work done in terms of force and displacement is,
Formula used : $W o r k d o n e = f o r c e \times d i s p l a c e m e n t$
$W = 10 m \times 5 = 50 m$
Step 5: To find mass,
Formula used : $p o w e r = \frac{w o r k}{t i m e}$
$900 = \frac{50 m}{40}$
$m = \frac{900 \times 40}{50}$
$= 720 k g$
Thus, $720 k g$ of water can be lifted.

Suggest Corrections

Similar questions

Calculate the time for which a motor pump of $10 H P$ and efficiency $80 %$ must be switched on, so as to pump $20 m^{3}$ of water through a vertical height of $20 m$ . [Density of water = $\frac{1000 k g}{m^{3}}$ , $g = \frac{10 m}{s^{2}}$ , $1 H P = 750 W$ ]

A load of $220 k g$ is vertically pulled up by a crane through a vertical height of $16 m$ in $40 s$ .the Calculate horsepower of the engine pulling the rope.

[Take g= $9.8 \frac{m}{s^{2}}$ $1 H P = 750 W$ ]

In a hydroelectric power station, $1000 k g$ of water is allowed to drop a height of $100 m$ in $1 s$ . If the conversion of potential energy to electric energy is $60 %$ , Calculate the power output. [Take $g = \frac{10 m}{s^{2}}$ ]

Q. Calculate the time for which a motor pump of 10 HP and efficiency 80% must be switched on, so as to pump 20m^3 of water through a vertical height of 20m. (Density of water=1000kgm^-3, g=10ms^-2, 1HP=750W)

A load of $220 k g$ is vertically pulled up by a crane through a vertical height of $16 m$ in $40 s$ . Calculate the total work done.

[Take g= $9.8 \frac{m}{s^{2}}$ ]

Join BYJU'S Learning Program

An electric pump is 60% efficient and is rated 2HP. Calculate the maximum amount of water it can lift through a height of 5m in 40s. [Take g=10ms2and 1HP=750W]

An electric pump is $60 %$ efficient and is rated $2 H P$ . Calculate the maximum amount of water it can lift through a height of $5 m$ in $40 s$ . [Take $g = \frac{10 m}{s^{2}}$ and $1 H P = 750 W$ ]