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Question

An electric pump is used to fill a tank of capacity 8 m3 kept at the height of 20 m from the ground. The pump takes 400 seconds to fill the tank by consuming 5 kW. The efficiency of pump is

A
60%
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B
30%
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C
80%
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D
40%
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Solution

The correct option is C 80%
The work done in filling the tank is = the increase in Potential energy.
increase in PE=mgh.

m=Volume(V)×density(ρ)

for water, ρ=1000kg/m3

m=8000kg
On earth, g=9.8m/s2

PE=8000×9.8×20 Joules

Energy spent by pump=power×time= 400×5000

% efficiency = work.done×100energy.spent
=8000×9.8×20×100400×5000

approx=80 %

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