An electric train in japan runs with a speed 1.3 Mach. It is approaching a station and blows a whistle of frequency 88 Hz. The frequency of the whistle heard by a stationary observer on the platform is :
A
800 Hz
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B
1600 Hz
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C
1040 Hz
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D
insufficient data.
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Solution
The correct option is A 800 Hz Doppler formula =f(v−vrv−vs)
Here Doppler Effect is applicable when the source and receiver speeds are lower than velocity of sound But source sound is higher in this case So Dopler Effect is not valid