An electrical applance has a rating 100 W, 120V. The resistance of element of appliance when in use is:

(a) $1.2 Ω$ (b) $144 Ω$ (c) $120 Ω$ (d) $100 Ω$

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Solution

(b) 144Ω

P=
$100 equals fraction numerator 120 cross times 120 over denominator R end fraction R equals fraction numerator 120 cross times 120 over denominator 100 end fraction equals 144 space o h m$

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