An electrical appliance has a rating 100 W, 120 V. The resistance of element of appliance when in use is :

1 \cdot 2 Ω

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144 Ω

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120 Ω

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100 Ω

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Solution

The correct option is B $144 Ω$
Electrical Power, $W = \frac{V^{2}}{R}$
Resistance, $R = \frac{V^{2}}{W}$
$R = \frac{120 \times 120}{100} Ω$
$R = 144 Ω$

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An electrical appliance has a rating 100 W, 120 V. The resistance of element of appliance when in use is :

The correct option is B 144ΩElectrical Power, W=V2RResistance, R=V2WR=120×120100ΩR=144Ω

The correct option is B $144 Ω$
Electrical Power, $W = \frac{V^{2}}{R}$
Resistance, $R = \frac{V^{2}}{W}$
$R = \frac{120 \times 120}{100} Ω$
$R = 144 Ω$